Answer:
First option.
Step-by-step explanation:
For a quadratic equation of the form:
a*x^2 + b*x + c = 0
we have that the solutions for x are:
[tex]x = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}[/tex]
where we have two solutions, one for each sign of the square root.
then if our equation is:
5x^2 + 3x - 4 = 0
we have that 5 = a, 3 = b and -4 = c, then our equation is:
[tex]x = \frac{-3 +- \sqrt{3^2 - 4*5*(-4)} }{2*5}[/tex]
then the correct option is the first one.
