Solve this problem on paper using all four steps. Ted weighs twice as much as Julie. Mike weighs three times as much as Julie. Together, Ted, Mike, and Julie weigh 210 lbs. What is the weight of each person? Julie weighs a0 pounds, Ted weighs a1 pounds, and Mike weighs a2 pounds.

Respuesta :

Answer:

Julie weighs 35 pounds, Ted weighs 70 pounds and Mike weighs 105 pounds.

Step-by-step explanation:

Ted weighs = t

Mike weighs = m

Julie weighs = j

First statement is given " Ted weighs twice as much as Julie."  t = 2j

Second statement "Mike weighs three times as much as Julie." m = 3j

Third statement Together weight 210 lbs.

= t + m + j = 210 lbs

= 2j + 3j + j = 210

= 6j = 210

j = 35 lbs

t = 35 × 2 = 70 lbs

m = 35 × 3 = 105 lbs

Julie weighs 35 pounds, Ted weighs 70 pounds and Mike weighs 105 pounds.

Answer:

Weight of Julie=35 lbs

Weight of Ted=[tex]70lbs[/tex]

Weight of Mike=[tex]105 lbs[/tex]

Step-by-step explanation:

Let weight of Julie=x

Weight of Ted=2x

Weight of Mike=3x

Sum of weight of three person=210 lbs

Substitute the values then we get

[tex]x+2x+3x=210[/tex]

Combine like terms

[tex]6x=210[/tex]

[tex]x=\frac{210}{6}[/tex]

Division property of equality

[tex]x=35[/tex]

Weight of Julie=35 lbs

Weight of Ted=[tex]2\times 35=70lbs[/tex]

Weight of Mike=[tex]3\times 35=105 lbs[/tex]