Respuesta :
[tex]b=0[/tex] and [tex]b=4[/tex] is the solution for the equation[tex]\frac{5}{3b^3-2b^2-5} =\frac{2}{b^3-2}[/tex]
What is equation?
In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =
According to question, we have the following equation:
[tex]\frac{5}{3b^3-2b^2-5} =\frac{2}{b^3-2}[/tex]
We have to find the solution.
We have the following equation:
[tex]\frac{5}{3b^3-2b^2-5} =\frac{2}{b^3-2}[/tex]
⇒[tex]5b^{3} - 6b^{3} = -4b^{2}[/tex]
⇒[tex]b^{2} (b - 4) = 0[/tex]
⇒[tex]b=0[/tex] and [tex]b=4[/tex]
Hence we can conclude that Option C is correct answer.
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