Answer:
This question is incomplete, here is the complete question;
"Consider the mirror shown here. An object 4 cm tall stands 10 cm in front of a converging mirror of focal length 5 cm.
The image formed by this mirror is: (Select all that apply.)
real
virtual
enlarged
the same size
diminished
Inverted
erect"
Answer: Virtual, Upright and Enlarged
Explanation:
The formula for image formed by a converging mirror is given by;
[tex]\frac{1}{f} =\frac{1}{u} +\frac{1}{v}[/tex] ------------------- eqn 1
where f = focal length = 5 cm
u = object height = 4 cm
v = image height = ?
substitute for u and f in eqn 1 to find v.
[tex]\frac{1}{5} =\frac{1}{4} +\frac{1}{v}[/tex]
[tex]\frac{1}{v} =\frac{1}{5} -\frac{1}{4}[/tex]
v = -20 cm
From the value of the image formed i.e -20 cm
The negative sign means the image is behind the mirror and this means image is;
1. Virtual
2. Upright
3. Enlarged
