Respuesta :
1. The surface that will be exposed to the rain is the lateral surface of the cylinder and the hemisphere.
2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.
3. the circumference of the base = 2[tex] \pi [/tex]r=2*[tex] \pi [/tex]*5=10[tex] \pi [/tex]
so the lateral area = 10[tex] \pi [/tex]*h=10[tex] \pi [/tex]*40=400[tex] \pi [/tex] ([tex]ft^{2} [/tex])
4. The surface area of a sphere is [tex]4 \pi r^{2} [/tex]
so the surface of the hemisphere = [tex] \frac{1}{2} *4 \pi r^{2}=2 \pi (5)^{2}=50 \pi [/tex]([tex]ft^{2} [/tex])
5. Total area exposed = 450[tex] \pi [/tex] [tex]ft^{2} [/tex]
2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.
3. the circumference of the base = 2[tex] \pi [/tex]r=2*[tex] \pi [/tex]*5=10[tex] \pi [/tex]
so the lateral area = 10[tex] \pi [/tex]*h=10[tex] \pi [/tex]*40=400[tex] \pi [/tex] ([tex]ft^{2} [/tex])
4. The surface area of a sphere is [tex]4 \pi r^{2} [/tex]
so the surface of the hemisphere = [tex] \frac{1}{2} *4 \pi r^{2}=2 \pi (5)^{2}=50 \pi [/tex]([tex]ft^{2} [/tex])
5. Total area exposed = 450[tex] \pi [/tex] [tex]ft^{2} [/tex]
