Bill wants to see how many times he needs to roll a standard number cube before getting a 5. What is the probability that Bill will roll a 5 on his third roll and not before?

a. 125/1296
b. 25/216
c. 1/6
d. 1/2

Respuesta :

coryn
5/6 • 5/6 • 1/6 = 25/216 the answer is b

Answer:

The answer is b. 25/216

Step-by-step explanation:

Bill wants to see how many times he needs to roll a standard number cube before getting a 5.

p = [tex]\frac{1}{6}[/tex] (on an average: roll 6 times before getting a 5)

The required probability can be found as :

[tex]\frac{1}{5}(\frac{5}{6}* \frac{5}{6}* \frac{5}{6})[/tex]

= [tex]\frac{5}{6}* \frac{5}{6}* \frac{1}{6}[/tex]

= [tex]\frac{25}{216}[/tex]

So, the answer is b. 25/216