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Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)
Place the correct coefficients in the difference.

x2y3 + _________xy2 + _________y

Respuesta :

Answer:

The coefficients are

11,-4 and 0

Step-by-step explanation:

We are given two algebraic expressions. We are subtracting the second from the first.

First one is

[tex]4x^2y^3+2xy^2-2y[/tex]

Second expression is

[tex]-7x^2y^3+6xy^2-2y[/tex]

The given expression

=[tex]4x^2y^3+2xy^2-2y-(-7x^2y^3+6xy^2-2y)\\=4x^2y^3+2xy^2-2y+7x^2y^3-6xy^2+2y\\=11x^2y^3-4xy^2+0y[/tex]

The coefficients are

11,-4 and 0

aksnkj

The correct expression for required difference is [tex]11x^2y^3-4xy^2+0y[/tex] and the correct coefficients in the difference are 11 for [tex]x^2y^3[/tex], -4 for [tex]xy^2[/tex], and 0 for y.

Given:

The given expression is [tex](4x^2y^3 + 2xy^2 -2y) - (-7x^2y^3 + 6xy^2 - 2y)[/tex].

It is required to solve the given expression and write it in a simple form.

While solving, similar terms can be added or subtracted.

The given expression can be simplified as,

[tex](4x^2y^3 + 2xy^2 -2y) - (-7x^2y^3 + 6xy^2 - 2y)=4x^2y^3 + 2xy^2 -2y+7x^2y^3 - 6xy^2 + 2y\\(4x^2y^3 + 2xy^2 -2y) - (-7x^2y^3 + 6xy^2 - 2y)=x^2y^3(4+7)+xy^2(2-6)+y(-2+2)\\(4x^2y^3 + 2xy^2 -2y) - (-7x^2y^3 + 6xy^2 - 2y)=11x^2y^3-4xy^2+0y[/tex]

Therefore, the correct expression for the required difference is [tex]11x^2y^3-4xy^2+0y[/tex] and the correct coefficients in the difference are 11 for [tex]x^2y^3[/tex], -4 for [tex]xy^2[/tex], and 0 for y.

For more details, refer to the link:

https://brainly.com/question/9703245