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A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:
p^2 +2pq+q^2=1

f(HH) = p2 =

f(Hh) = 2pq =

f(hh) = q2 =

Respuesta :

f(HH)  =  p2   =  0.04

f(Hh)  =   2pq  =   ⇒ 0.32,.32

f(hh)  =   q2   =   ⇒ 0.64,.64

     

Hardy Weinberg Equation is a mathematical expression, which is used to calculate the genetic variation in a given population at equilibrium. The genetic variation is calculated by using:

[tex]\rm p^2 + 2pq +q^2 = 1[/tex]

How to calculate allelic frequency?

Given:

Allele frequency for dominant alelle = 0.2

Allele frequency for recessive allele = 0.8

Hardy Weinberg Equation:

[tex]\rm p^2 + 2pq +q^2 = 1[/tex]

Where,

[tex]\rm p^2[/tex] = dominant purebred allele frequency (HH)

[tex]\rm q^2[/tex] = recessive purebered allele frequency (hh)

2pq =  heterozygous allele frequency (Hh)

Now, putting the given values in the above equation we get:

[tex](0.2)^2 + 2 (0.2 \times 0.8) + (0.8)^2 = 1\\\\0.04 + 0.32 + 0.64 = 1[/tex]

Thus, the frequency for different allelic frequencies are:

[tex]\rm p^2[/tex] = 0.04

[tex]\rm q^2[/tex] = 0.64

2 pq = 0.32

Learn more about Hardy Weinberg equation here:

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