Respuesta :
The given function is f(a)=[tex]-2a^{2}-5a+4.[/tex])
The question is asking us to find f(-3)
To find f(-3) we replace a by -3.
f(-3)=[tex]-2(-3)^{2}-5(-3)+4[/tex]
f(-3) =-2(9)+15+4
f(-3)=-18+15+4
f(-3)= -18+19
f(-3)= 1
Answer:
The value of f(–3) for expression f(a) = –2a² – 5a + 4 is 1 .
Step-by-step explanation:
As given the expression in the question be as follow.
f(a) = –2a² – 5a + 4
Put a = -3 in the above value
f(-3) = –2 × -3 × -3 – 5 × -3 + 4
f(-3) = - 18 + 15+ 4
f(-3) = - 3 + 4
f(-3) = 1
Therefore the value of f(–3) for expression f(a) = –2a² – 5a + 4 is 1 .
