A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of the cubes?

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Answer:

A.      (4x^2-6y)(16x^4+24x^2y+36y^2)

Step-by-step explanation:


We are required to find the difference in the volume of the cubes

The difference in the volume of the cubes is 4(4x⁴ - 9y²)

side length of small cube = 6y

volume of small cube = (side length)²

= (6y)²

side length of larger cube = 4x²

volume of larger cube = (side length)²

= (4x²)²

Difference in volume = volume of larger cube - volume of small cube

= (4x²)² - (6y)²

= (4x²)(4x²) - 36y²

= 16x⁴ - 36y²

= 4(4x⁴ - 9y²)

Therefore, the difference in the volume of the cubes is 4(4x⁴ - 9y²)

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