Respuesta :

taskmasters
In order to get the magnitude of the electric field at the location of the test charge, you have to use the formula: E=Fe/q.
Given E as electric field strength; Fe as electric force = 0.751 N and q as charge = 5*10-5 C. Therefore,
E= 0.751 N / 5 * 10-5 CE=15020 N C-1 or V m-1 Electric field at the location.
pstnonsonjoku

The electric filed intensity is calculated from the data as 15020 N/C.

What is electric field?

The electric field refers to the region in space where the effect of an electric charge is felt.

Given that the electric field is given by;

E = F/q

F =  0.751  N

q = 5.00 * 10^-5 C

E = 0.751  N/5.00 * 10^-5 C

E= 15020 N/C

Learn more about electric field:https://brainly.com/question/15800304

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