The equation for a circle is x2−8x+y2−2y−8=0 .

What is the equation of the circle in standard form?

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minimangalsathyan minimangalsathyan · Answer 1 · 2017-06-13T15:45:00+02:00

the eq of the circle in standard form is x^2+y^2+2ux+2vy +d=0 where (-u,-v) is the centre and sq root of u^2+v^2-d is the radius

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virtuematane virtuematane · Answer 2 · 2019-06-10T13:06:46+02:00

Answer:

The equation of the given circle in standard form is:

[tex](x-4)^2+(y-1)^2=5^2[/tex]

Step-by-step explanation:

The standard form of a circle is given by the equation:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where (h,k) represent the center of the circle and r denotes the radius of the circle.

Hence, we are given equation as:

[tex]x^2-8x+y^2-2y-8=0[/tex]

On solving as follows:

[tex]x^2+(4)^2-8x+y^2+1^2-2y-(4)^2-1^2-8=0\\\\\\(x-4)^2+(y-1)^2-25=0\\\\\\(x-4)^2+(y-1)^2=25\\\\\\(x-4)^2+(y-1)^2=5^2[/tex]