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An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it falls is represented by the equation S(t) = –16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air?

Respuesta :

HomertheGenius
The distance ( S ) is represented by the equation:
S ( t ) = - 16 t² + 25
- 16 t² + 25 = 0
- 16 t² = - 25  / · ( - 1 )
16 t² = 25
t ² = 25 / 16 
t = √( 25/16) = 5/4 = 1.25 s  ( we will not accept the negative value )
Answer:
The acorn is moving trough the air for 1.25 seconds.

Answer:

o<t<5/4

Step-by-step explanation:

I just took the test and got it correct

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