Respuesta :

Answer-

P(C|Y) of the information in the table was found to be 0.5

Solution-

We know from the formula for conditional probability that,

[tex]P(B\mid A)=\frac{P(A \ and \ B)}{P(A)}[/tex]

Applying the same,

[tex]P(C\mid Y)=\frac{P(C \ and \ Y)}{P(Y)}[/tex]

Calculating the values,

[tex]Probability \ of \ an \ event =\frac{favorable \ outcomes}{possible \ outcomes}[/tex]

[tex]P(C)=\frac{40}{146}=\frac{20}{73} \ and \ P(Y)=\frac{30}{146}=\frac{15}{73}[/tex]

[tex]P(C \ and \ Y)=\frac{15}{146}[/tex]

[tex]\therefore P(C\mid Y)=\frac{\frac{15}{146}}{\frac{15}{73}} =\frac{73}{146} =0.5[/tex]


The probability P(C|Y) means the probability of C given Y, and the value of the probability P(C|Y) is 0.5

How to determine the probability?

The probability notation is given as: P(C|Y)

To do this, we make use of the following conditional probability formula

P(C|Y)= n(C and Y)/n(Y)

From the table, we have:

n(C and Y) =15

n(Y) =30

So, the probability equation becomes

P(C|Y)= 15/30

Evaluate the quotient

P(C|Y)= 0.5

Hence, the value of the probability P(C|Y) is 0.5

Read more about probability at:

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