Respuesta :
Unique pair of dates...use "n choose k" formula:
n!/(k!(n-k)!), n=number of total possible choices, k=number of selections
365!/(2!(363!))
66430 unique combinations
n!/(k!(n-k)!), n=number of total possible choices, k=number of selections
365!/(2!(363!))
66430 unique combinations
The first date has 365 possible outcome
The second date has 364 possible outcome (since one day already selected)
The total outcome is 365 x 364 =132,860 outcomes
The second date has 364 possible outcome (since one day already selected)
The total outcome is 365 x 364 =132,860 outcomes