Respuesta :
the answer is the 1-1, 2-4,3-2,4-3... hope it helps and yall understand these.. :)
Answer: a book with a mass of 0.75 kilograms resting on a shelf at a height of 1.5 meters< a ball with a mass of 0.25 kilograms rolling on flat ground with a velocity of 10 meters/second< a stone with a mass of 0.7 kilograms being held still at a height of 7 meters< a mass of 2.5 kilograms falling with a velocity of 10 meters/second when it’s 4 meters above ground
Explanation: Gravitational potential energy is the energy possessed by an object due to its position or height.Kinetic energy is the energy possessed by an object by virtue of its motion.
[tex]P.E=m\times g\times h[/tex]
m= mass of object
g= gravity
h= height of an object
[tex]K.E=\frac{1}{2}\times mv^2[/tex]
v= velocity of object
[tex](1kgm^2s^{-2}=1Joule)[/tex]
A) a book with a mass of 0.75 kilograms resting on a shelf at a height of 1.5 meters
[tex]P.E=0.75kg\times 9.8ms^{-2}\times 1.5m=11.025J[/tex]
B) a mass of 2.5 kilograms falling with a velocity of 10 meters/second when it’s 4 meters above ground
[tex]K.E=\frac{1}{2}\times mv^2[/tex]
[tex]K.E=\frac{1}{2}\times 2.5kg\times (10)^2=125J[/tex]
[tex]P.E=m\times g\times h[/tex]
[tex]P.E=2.5\times 9.8\times 4=98J[/tex]
total energy= (K.E+P.E) =(125+98) =223J
C) a ball with a mass of 0.25 kilograms rolling on flat ground with a velocity of 10 meters/second
[tex]K.E=\frac{1}{2}\times mv^2[/tex]
[tex]K.E=\frac{1}{2}\times 0.25\times (10m/s)^2=12.5J[/tex]
D) a stone with a mass of 0.7 kilograms being held still at a height of 7 meters
[tex]P.E=0.7kg\times 9.8ms^{-2}\times 7m=48.02J[/tex]
