The area of any Rhombus = [tex]\frac{1}{2}x product of the diagonals .[/tex]
Diagonals of Rhombus bisect each other at right angles.
The Length of the diagonals are 4+4=8 and 3+3=6.
Area of the Rhombus = [tex]\frac{1}{2}x8x6.=\frac{48}{2}=24.[/tex]
Area of the given Rhombus is 24 square units.
Answer: The area of the rhombus is 24 square units.
Step-by-step explanation:
We are given a rhombus having two diagonals.
[tex]d_1=4+4=8units\\d_2=3+3=6units[/tex]
To calculate the area of the rhombus, we use the formula:
[tex]Area=\frac{d_1\times d_2}{2}[/tex]
Putting values in above equation, we get:
[tex]\text{Area of rhombus}=\frac{8\times 6}{2}=\frac{48}{2}=24\text{ sq. units}[/tex]
Hence, the area of the rhombus is 24 square units.
