The least number of buses needed to carry 710 passengers is 11 buses.
Given:
1 bus=1 to 70 passengers
2 buses=71 to 140 passengers
3 buses=141 to 210 passengers
4 buses=211 to 280 passengers
5 buses=281 to 350 passengers
Hence:
Additional buses will be:
6 buses=350 to 710 passengers
Least number of buses=6 buses+ (710 - 350)/ 70
Least number of buses= 6 buses+ 360 / 70
Least number of buses = 6 buses+ 5 buses
Least number of buses=11 buses
Therefore the least number of buses needed to carry 710 passengers is 11 buses.
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