A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relation h= -7.3t^2 + 8.25t +2.1, where h is the height in meters, and t is the time in seconds, since the ball was released
This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation; h=-7.3t^2+8.25t+2.1+5 The time taken for the ball to hit the ground will be given as falls; -7.3t^2+8.25t+7.1=0 to solve for t we use the quadratic formula; t=[-b+/-sqrt(b^2-4ac)]/(2a) a=-7.3, b=8.25, c=2.1 t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3) t= -0.572 or t=1.702 since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
