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What mass of propane is necessary to react with the amount of oxygen in the chemical formula C3H8 + 5O2 → 3CO2 + 4H2O

Respuesta :

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

n(O₂)=1.407 mol
M(C₃H₈)=44.1 g/mol

m(C₃H₈)/M(C₃H₈)=n(O₂)/5

m(C₃H₈)=M(C₃H₈)n(O₂)/5

m(C₃H₈)=44.1*1.407/5=12.410 g

the mass of propane is 12.410 g
mickymike92

The mass of propane required to react with 5 moles of oxygen is 44 g.

What mass of propane is required?

According to the equation of the reaction, 1 mole of propane reacts with 5 moles of oxygen.

Molar mass of propane is 44 g/mol.

Therefore, the mass of propane required is 44g.

Learn more about molar mass at: https://brainly.com/question/15476873

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