Your question is related to the binomial probability
Although there is no picture, I will answer your question that is:
Find the probability of getting exactly 5 “heads” in 10 coin flips
Probability of getting a head = 1/5 and also 1/2 for getting a tail.
P(H) =1/2 and P(T) =1/2
Total # of flips =10; Total # Heads requested = 5
¹⁰C₅ = (PH)⁵.P(T)¹⁰⁻⁵
¹⁰C₅ = (1/2)⁵.P(1/2)⁵ = 63/256 (answer B)
