jag1900
contestada

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 8, -14, and 3 + 9i

Respuesta :

hello : 
f(x) = (x-8)(x+14)(x-3-9i)....minimum degree is : 3
f(x) = (x²+6x-112)(x-3-9i)
f(x) = ....calulate ln 
polynomial in standard form

Answer:

Step-by-step explanation:

To start you need to find the factorials of 8, -14, and 3 + 9i.

The factorials of these numbers are:

8: x - 8 = 0

-14: x + 14 = 0

3 + 9i: x - 3 - 9i = 0 *

3 - 9i: x - 3 + 9i = 0 *

(If you look in the files it shows how I got these numbers)

Next, you need to multiply the factorials together.

(x - 3 - 9i)(x - 3 + 9i) = x^2 - 6x + 90

Take that and multiply by your next factorial:

(x + 14)(x^2 - 6x + 90) = x^3 + 8x^2 + 6x + 1260

Multiply that by your final factorial and you have you final answer!

(x - 8)(x^3 + 8x^2 + 6x + 1260) = x^4 + 58x^2 + 1212x - 10,080

I hoped this helped!

f(x) = x² - 303x² + 1212x - 10,080

*When you have 3 + 9i or anything along the lines of that then you need to find the inverse of it. You simply you simply change the sign that goes before the i term. Change 3 + 9i to 3 - 9i