Respuesta :
The equation of a circle is:
(x-h)^2+(y-k)^2=r^2
Where (h,k) is the center of the circle and r is the radius of the circle. In this case we have (6,1) for the center and a radius of 5 so:
(x-6)^2+(y-1)^2=25
So any point that satisfies that equation lies on the circle.
(x-h)^2+(y-k)^2=r^2
Where (h,k) is the center of the circle and r is the radius of the circle. In this case we have (6,1) for the center and a radius of 5 so:
(x-6)^2+(y-1)^2=25
So any point that satisfies that equation lies on the circle.
Add tye radius with the X coordinate
(6+5,1 ) = (9,1)
Then subtract it from X
Or add & subtract the radius with the Y axis
And you will get the answer
(6+5,1 ) = (9,1)
Then subtract it from X
Or add & subtract the radius with the Y axis
And you will get the answer