Respuesta :
M(Li)=6.94 g/mol
n(Li)=5.50 mol
m(Li)=n(Li)M(Li)
m(Li)=5.40*6.94=37.476 g≈37.5
m(Li)=37.5 g
n(Li)=5.50 mol
m(Li)=n(Li)M(Li)
m(Li)=5.40*6.94=37.476 g≈37.5
m(Li)=37.5 g
Answer:
37.5 g
Explanation:
First you should kwow the molar mass of the lithium, so you can use your periodic table.
Molar mass of lithium = [tex]6.941\frac{g}{mol}[/tex]
Then you should relate the molar mass of the lithium with the quantity of moles the problem gives you:
[tex]5.40molesoflithium*\frac{6.941goflithium}{1moloflithium}=[/tex]37.48 g of lithium
Rounding the answer
37.5 g of lithium