Answer:
The answer is "D" NO SOLUTION.
Step-by-step explanation:
I must correct your given equation because it must read like this:
(3/(m+3)) - (m/(3-m)) = (m∧2+9)/(m∧2-9)
Now we can solve it:
First we will transfer the fraction from the right to the left side of the equation.
(3/(m+3)) - (m/(3-m)) - (m∧2+9)/(m∧2-9) = 0
We will change binomial sign (3-m) = - (m-3) and that change sign of the second fraction from - to + , also we will change (m∧2-9) which is difference squared to (m-3)(m+3) and we get:
(3/(m+3)) + (m/(m-3)) - (m∧2+9)/(m-3)(m+3) = 0
The smallest common denominator for this equation is (m+3)(m-3)
when we multiply entire equation with (m+3)(m-3) we get:
3·(m-3) + m·(m+3)-(m∧2+9) = 0 => 3m-9+m∧2+3m-m∧2-9=0 =>
6m-18=0 => 6m=18 => m=18/6 = 3 => m=3
But we have conditions (m+3)(m-3) ≠ 0 => m+3≠0 and m-3≠0 => m≠-3 and m≠3
We conclude that this equation does not have solution.
Good luck!!!
