A helium balloon is filled in a store at room temperature (24°C) to a volume of 6.5 L. The balloon is then taken outside where the temperature is only 8°C. What is the new volume of the balloon? 6.1 L 6.9 L 2.2 L 19 L

Respuesta :

Applying Charles' Law, in which as volume increases, temperature increases and as it decreases, the temperature also decreases. Hence, [tex] \frac{ V_{1} }{ T_{1} } = \frac{ V_{2} }{ T_{2} } [/tex]

[tex]V_{1} = 6.5 L \\ T_{1} = (24 + 273) \\ V_{2} = X \\ T_{2} = (8 + 273) [/tex]
note: Temperature in Celsius shall be converted to Kelvin

Simplifying:
[tex] \frac{6.5}{297} = \frac{X}{281} [/tex]

x = { 6.5 (281) } / 297 
x = 6.1 L


Answer:

6.1 L

Explanation: