alexwing285
contestada

What is the product?
[tex] \frac{2a-7}{a}* \frac{3a^2}{2a^2-11a+14} [/tex]

A. [tex] \frac{3}{a-2} [/tex]
B. [tex] \frac{3a}{a-2} [/tex]
C. [tex] \frac{3a}{a+2} [/tex]
D. [tex] \frac{3}{a+2} [/tex]

Respuesta :

tonb
The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with:

[tex]\frac{3a^2}{a(a-2)} \implies \frac{3a}{a-2} [/tex]

Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.


Epikkobra
B. 3a/a-2
im taking it

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