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Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground?

Hint: Use H(t) = −16t2 + vt + s.

Answer (1) 4.64 seconds

Answer (2) 2.94 seconds

Answer (3) 2.28 seconds

Answer (4) 0.08 second

Respuesta :

Answer:

Option (1). 4.64 seconds.

Step-by-step explanation:

It is given in the question that a baseball pitcher was at an initial height of 6 feet.

Velocity of the ball is 73 feet per second.

The expression that represents the event is

H(t) = -16t² + vt + s

Here s = initial height = 6 ft.

H(t) = 0

velocity of the ball = 73 feet per second

The expression will be

-16t² + 73t + 6 = 0

Now we will get the solution for t.

[tex]t=\frac{-73\pm \sqrt{(73)^{2}+4\times 16\times 6}}{2(-16)}[/tex]

[tex]=\frac{-73\pm \sqrt{5329+384}}{-(32)}=\frac{-73\pm 75.58}{-32}[/tex]

[tex]t=-.081[/tex] and [tex]t=4.64[/tex]

Time can not be negative so t = 4.64 sec is the answer.

Option 1). 4.64 is the answer.

The values of t are 4.64 and -0.08. Neglecting -0.08 because time can never be less than 0. Option 1 is correct.

What is the polynomial?

Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.

Given

Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second.

H(t) = −16t² + vt + s.

How long does it take the ball to hit the ground?

The initial height of 6 feet, with a velocity of 73 feet per second.

H(t) = 0, s = 6, and v = 73 then equation will be

H(t) = −16t² + vt + s.

   0 = −16t² + 73t + 6.

It is a quadratic polynomial, the solution of this is given by

16t² - 73t - 6 = 0

On solving this equation the values of t are 4.64 and -0.08.

Neglecting -0.08 because time can never be less than 0.

Thus, option 1 is correct.

More about the Polynomial link is given below.

https://brainly.com/question/17822016