the americans with disabilities act sets the maximum angle of a wheelchair ramp entering a business at 4.76. Determine the horizontal distance needed to accommodate a ramp that goes up to a door 4 feet of the ground.

tanα=h/d, where α=angle of elevation, h=height, d=horizontal distance.

d=h/tanα, we are given that h=4ft and α=4.76° so

d=4/tan4.76° ft

d≈48.04 ft (to nearest hundredth of a foot)

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shubhamchouhanvrVT shubhamchouhanvrVT · Answer 2 · 2022-05-17T16:03:45+02:00

The value of horizontal distance is needed to accommodate a ramp that goes up to a door 4 feet of the ground will be d≈48.04 ft

What is trigonometry?

Trigonometry is the relationship between the sides of the triangle and the angle of the right angle triangle. It contains the angle Sin,Cos,Sec,tan,Coses etc.

[tex]tan\theta=\dfrac{h}{d},[/tex]

where [tex]\theta[/tex]=angle of elevation, h=height, d=horizontal distance.

[tex]d=\dfrac{h}{tan\theta}[/tex],

we are given that h=4ft and [tex]\theta[/tex]=4.76° so

[tex]d=\dfrac{4}{tan4.76^o}\ ft[/tex]

d≈48.04 ft (to nearest hundredth of a foot)

Hence the value of horizontal distance is needed to accommodate a ramp that goes up to a door 4 feet of the ground will be d≈48.04 ft

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