amanyk
contestada

FACTOR:

2x^2-17x-33

and find the extraneous soultion, if there is any.

ALL WORK SHOWN (or at least most of it)
thank you!!!

Respuesta :

irspow
2x^2-17x-33=0  let's complete the square, add 33 to both sides

2x^2-17x=33  make the leading coefficient equal to one, divide all by 2

x^2-8.5=16.5  halve the linear coefficient, square it, and add that to both sides

x^2-8.5+18.0625=34.5625  now left side is a perfect square

(x-4.25)^2=34.5625  take the square root of both sides

x-4.25=±√34.5625  add 4.25 to both sides

x=4.25±√34.5625 so the factors are:

(x+4.25+√34.5625)(x+4.25-√34.5625)
[tex]2x^2-17x-33 : \text{Factor} [/tex] 

[tex]a(x- \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, x-\dfrac{-b- \sqrt{b^2-4ac} }{2a} [/tex] 

[tex]2(x- \dfrac{17+ \sqrt{(-17)^2}-4*2*-33 }{2*2}, x-\dfrac{17- \sqrt{(-17)^2}-4*2*-33 }{2*2} [/tex] 

[tex]2(x- \dfrac{17+ \sqrt{553} }{ 4}, x- \dfrac{17- \sqrt{553} }{ 4})[/tex]

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