Answer:
For the student who scored 560,zvalue is 0.7257 or 72.57%.
For the student who scored 450, zvalue is 0.3085 or 30.85%.
For the student who scored 640, zvalue is 0.9192 or 91.92%.
For the student who scored 530, zvalue is 0.6179 or 61.79%.
Step-by-step explanation:
Z-value for each of the students are 0.7257 or 72.57%, 0.3085 or 30.85%, 0.9192 or 91.92%, and 0.6179 or 61.79% respectively.
It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.
We have:
Four students took a national standardized test for which the mean was 500 and the standard deviation was 100.
We know,
Z = (X-μ)/σ
For the student who scored 560:
Z = (560-500)/100 = 0.6
Z at 0.6 is 0.7257 or 72.57%
For the student who scored 450:
Z = (450-500)/100 = -0.5
Z at -0.5 is 0.3085 or 30.85%
For the student who scored 640:
Z = (640-500)/100 = 1.4
Z at 1.4 is 0.9192 or 91.92%
For the student who scored 530:
Z = (530-500)/100 = 0.3
Z at 0.6 is 0.6179 or 61.79%
Thus, Z-value for each of the students are 0.7257 or 72.57%, 0.3085 or 30.85%, 0.9192 or 91.92%, and 0.6179 or 61.79% respectively.
Learn more about the normal distribution here:
brainly.com/question/12421652
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