Respuesta :
Answer: The maximum number of cookies eaten by Jim is 10.
Step-by-step explanation:
Since we have given that
Total number of cookies n(U) = 80
Number of cookies containing vanilla n(V) = 40
Number of cookies containing nuts n(N) = 45
Number of cookies containing both n(V∩N) = 15
So, we get that
[tex]n(V\cup N)=n(V)+n(N)-n(V\cap N)\\\\n(V\cup N)=40+45-15\\\\n(V\cup N)=85-15\\\\n(V\cup N)=70[/tex]
Since Jim is allergic to both nuts and vanilla, but he loves cookies.
So, number of cookies eaten by Jim which is neither nuts nor vanilla.
[tex]n(V\cup N)'=n(U)-n(V\cup N)\\\\n(V\cup N)'=80-70\\\\n(V\cup N)'=10[/tex]
Hence, the maximum number of cookies eaten by Jim is 10.
If his mother has baked 80 cookies. The largest number of cookies that Jim can eat on Billy’s birthday is 10 cookies.
Number of cookies
First step
Number of nuts = 45 - 15
Number of nut = 30
Second step
Number of nuts and vanilla = 30 + 40
Number of nuts and vanilla = 70
Third step
Number of cookies= 80 - 70
Number of cookies= 10 cookies
Therefore the largest number of cookies that Jim can eat on Billy’s birthday is 10 cookies.
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