Answer:
Option 2 is correct.
Step-by-step explanation:
We will evaluate the given functions as:
(fog)(x)=f(g(x))
Case1:
[tex]f(x)=x^2\text{and}g(x)=\frac{1}{x}[/tex]
[tex](fog)(x)=f(\frac{1}{x})=(\frac{1}{x})^2[/tex]
Which is not a function because it will not give different values of y for different values of x.
Case2:
[tex]f(x)=\frac{2}{x}\text{and}g(x)=\frac{2}{x}[/tex]
[tex](fog)(x)=f(\frac{2}{x})=(\frac{2}{\frac{2}{x}})=x[/tex]
This will give different values of y for different values of x
Hence, Option 2 is correct.
