Answer: molecular shape of [tex]BF_3[/tex] is trigonal planar.
Explanation: Formula used
[tex]:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A][/tex]
where, V = number of valence electrons present in central atom i.e. boron = 3
N = number of monovalent atoms bonded to central atom=3
C = charge of cation = 0
A = charge of anion = 0
[tex]BF_3:[/tex]
[tex]{\text{Number of electrons}} =\frac{1}{2}[3+3-0+0]=3[/tex]
The number of electrons is 3 that means the hybridization will be [tex]sp^2[/tex] and the electronic geometry of the molecule will be trigonal planar.
