- To find between what two consecutive whole numbers the square root of a number is, we find the perfect square of each number, until the result passes the desired number.
- Whole numbers: Countable, that is, 0, 1, 2,3,...
- The square of a number x is [tex]x^2[/tex]
Doing this, we get that the square root of 68 lies between 8 and 9.
Squares:
- The square of 0 is [tex]0^2 = 0[/tex]
- The square of 1 is [tex]1^2 = 1[/tex]
- The square of 2 is [tex]2^2 = 4[/tex]
- The square of 3 is [tex]3^2 = 9[/tex]
- The square of 4 is [tex]4^2 = 16[/tex]
- The square of 5 is [tex]5^2 = 25[/tex]
- The square of 6 is [tex]6^2 = 36[/tex]
- The square of 7 is [tex]7^2 = 49[/tex]
- The square of 8 is [tex]8^2 = 64[/tex]
- The square of 9 is [tex]9^2 = 81[/tex]
68 is between, 64 and 81, thus, the square root of 68 is between the square root of 64 and the square root of 81, that is, the square root of 68 is between 8 and 9.
A similar example is given at https://brainly.com/question/17698237
