Respuesta :
Answer:
[tex]m=14.6g[/tex]
Explanation:
You can use the equation [tex]Q=cm(T_{2}-T_{1})[/tex] where Q is the heat, c is the specific heat of the substance, [tex]T_{2}[/tex] and [tex]T_{1}[/tex] are temperature and m is the mass of the substance.
Solving for m we have:
[tex]m=\frac{Q}{c(T_{2}-T_{1})}[/tex]
The problem gives you the information about the variables:
[tex]Q=350J[/tex]
[tex]c=1.2\frac{J}{g^{o}C}[/tex]
[tex]T_{1}=10.0^{o}C[/tex]
[tex]T_{2}=30.0^{o}C[/tex]
Replacing that values:
[tex]m=\frac{350J}{1.2\frac{J}{g^{o}C}(30.0^{o}C-10.0^{o}C)}[/tex]
[tex]m=\frac{350J}{1.2\frac{J}{g^{o}C}(20.0^{o}C)}[/tex]
[tex]m=14.6g[/tex]
