Jasmine had a carrot cake with cream cheese frosting for her birthday .she and her friend each ate 1/4 of the cake and jasmine's brother ate 1/3 of the cake.jamines mom and dad shared the remaining cake evenly.what fractions of the cake did jasmines parents each eat?

Respuesta :

Hey there!

To solve this problem, you first would need to solve for how much of the cake is left after Jasmine, her friend, and Jasmine's brother got their slices. Then, you would need to split the remaining amount in half to get the answer of what each parent ate. We would need to make all of the denominators the same, so let's make all of the fractions out of 12, a common denominator of 3 and 4. 

[tex]\frac{12}{12} - \frac{1}{4} - \frac{1}{4} - \frac{1}{3}[/tex]
[tex]\frac{12}{12} - \frac{3}{12} - \frac{3}{12} - \frac{4}{12}[/tex]
[tex] \frac{12}{12} - \frac{10}{12} = \frac{2}{12} [/tex]

It can then be concluded that each parent ate [tex] \frac{1}{12} [/tex] of the cake, since there was [tex] \frac{2}{12} [/tex] remaining. 

You can check this answer by adding up all of the parts we used in this problem:

[tex]\frac{3}{12} + \frac{3}{12} + \frac{4}{12} + \frac{1}{12} + \frac{1}{12} = \frac{12}{12}[/tex]

Hope this helped you out! :-)

Answer:

For a simple answer, here...

It can then be concluded that each parent ate 1/12  of the cake, since there was 2/12 remaining.

Step-by-step explanation:

Hope this helps!

Have a great day! :)