Respuesta :
Answer:
The zeros of the given function [tex]f(x)=x^2+17x+72[/tex] is [tex]\left(x+8\right)\left(x+9\right)[/tex] are -8 and -9.
Step-by-step explanation:
Given : Function [tex]f(x)=x^2+17x+72[/tex]
We have to find the zeros of the functions.
Consider the given Function [tex]f(x)=x^2+17x+72[/tex]
Since, we have to find the zeros of the given functions.
Put f(x) = 0
Thus, [tex]x^2+17x+72=0[/tex]
We can solve the given equation using middle term splitting method.
17x can be written as 8x + 9x
[tex]x^2+17x+72=0[/tex] can be written as [tex]x^2+8x+9x+72=0[/tex]
Taking x common from first two term and 9 common from last two terms, we have,
[tex]x(x+8)+9(x+8)=0[/tex]
Simplify, we have,
[tex]\left(x+8\right)=0[/tex] or [tex](x+9\right)=0[/tex]
x = -8 and x = -9
Apply zero product rule,[tex]a\cdot b= 0 \Rightarrow a=0 \ or \ b=0[/tex]
[tex]\left(x+8\right)\left(x+9\right)=0[/tex]
Thus, The zero of the given function [tex]f(x)=x^2+17x+72[/tex] is [tex]\left(x+8\right)\left(x+9\right)[/tex] are -8 and -9.
Answer:
-8 and -9 are correct!
Step-by-step explanation:
I took the test :)
