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A baker has a bag of flour that is 11% whole wheat and a bag of flour that is 63% whole wheat. How many cups of each type does the baker need to make 12 cups of a flour mixture that is 50% whole wheat?

Respuesta :

use three cups of flour that is 11% whole wheat and 9 cups of 63%

Answer: There are 3 cups of first type of whole wheat and 9 cups of second type of whole wheat.

Step-by-step explanation:

Since we have given that

Concentration of flour in first bag of flour = 11%

Concentration of flour in second bag of flour = 63%

Flour mixture contains 50% of whole wheat

So, we will use "Mixture and Allegation"

Ist bag of flour     IInd bag of flour

  11                               63

                 50

----------------------------------------

63-50            :          50-11

13                   :             39

1                     :             3

Since there are 12 cups of a flour mixture .

So, Number of cups of first type of whole wheat is given by

[tex]\frac{1}{4}\times 12\\\\=3[/tex]

Number of cups of second type of whole wheat is given by

[tex]\frac{3}{4}\times 12\\\\=3\times 3\\\\=9[/tex]

Hence, there are 3 cups of first type of whole wheat and 9 cups of second type of whole wheat.

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