Answer:
The confidence interval is (23.888, 24.112)
Step-by-step explanation:
The restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average. So, the mean is 24 ounces.
Standard Deviation = 0.4
Number of bottles used for sample = 49, so n = 49
Confidence level = 95% or 0.95
z=1.96
Hence, the confidence interval is given by the expression:
[tex]24+1.96*\frac{0.4}{\sqrt{49} }[/tex] and
[tex]24-1.96*\frac{0.4}{\sqrt{49} }[/tex]
Hence, Confidence interval = (23.888, 24.112)
