Respuesta :

start off by "switching" the variables

[tex]\bf 5\boxed{y}+4=(\boxed{x}+3)^2+\cfrac{1}{2}\qquad inverse\implies 5\boxed{x}+4=(\boxed{y}+3)^2+\cfrac{1}{2}[/tex]

then solve for "y"

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