The function f(x)=x^2+2x-8 has zeros of -4 and 2.
The zero of a real-, complex-, or generally vector-valued function f, is
a member x of the domain of function such that f(x)=0 at x; x is the solution to the equation f(x) = 0.
As we have the zeros -4 and 2
The function can be
f(x)=(x-2)(x+4)
f(x)=x^2+2x-8.
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