If f(x) 2x2 8x 9, which statement regarding the vertex form of f(x) is true? A. In vertex form, f(x) 2(x 2)2 1 and therefore has a minimum value of 1 B. In vertex form, f(x) 2 (x 2)2 1 and therefore has a minimum value of 2. C. In vertex form, f(x) 2(x 2)2 4.5 and therefore has a minimum value of 4.5 D. In vertex form, f(x) 2(x 2)2 4.5 and therefore has a minimum value of 2.

Respuesta :

it would be eleven plus ten times the 3 roman numeral y=mx+b

In vertex form, the formula is [tex]f(x) = 2\cdot (x+2)^{2}+1[/tex] and therefore has a minimum value of 1. (Correct choice: A)

How to determine the vertex in parabola formula

In this question we must complete the square and factor the resulting expression to determine coordinates of the vertex:

[tex]f(x) = 2\cdot x^{2}+8\cdot x +9[/tex]

[tex]f(x) = 2\cdot (x^{2}+4\cdot x +4.5)[/tex]

[tex]f(x) = 2\cdot (x^{2}+4\cdot x + 4)+1[/tex]

[tex]f(x) = 2\cdot (x+2)^{2}+1[/tex]

Thus, in vertex form, the formula is [tex]f(x) = 2\cdot (x+2)^{2}+1[/tex] and therefore has a minimum value of 1. (Correct choice: A) [tex]\blacksquare[/tex]

Remark

Statement presents typing mistakes and is poorly formatted. Correct form is shown below:

If [tex]f(x) = 2\cdot x ^{2}-8\cdot x +9[/tex], which statement regarding the vertex form of [tex]f(x)[/tex] is true?

A. In vertex form, [tex]f(x) = 2\cdot (x-2)^{2}+1[/tex] and therefore has a minimum value of 1.

B. In vertex form, [tex]f(x) = 2\cdot (x-2)^{2}+1[/tex] and therefore has a minimum value of 2.

C. In vertex form, [tex]f(x) = 2\cdot (x-2)^{2}+4.5[/tex] and therefore has a minimum value of 4.5.

D. In vertex form, [tex]f(x) = 2\cdot (x-2)^{2}+4.5[/tex] and therefore has a minimum value of 2.

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