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MissPhiladelphia
The characteristic of an Iodine which has a much higher vapour pressure could be held responsible of its spontaneous sublimation. Even though is has a greater intermolecular force (Van der Waals), it would still have the tendency to change the phase into a gaseous state when the pressure reaches 1 atm.

The explanation of iodine spontaneously should be explained below.

Sublimation reaction:

It should be  sublimation reaction: I2(s) <=> I2(g)

And,

Reaction quotient Qp = P(I2),

where P(I2) is the iodine partial pressure in atm.

Now

ΔG = ΔGo + RT lnQp = ΔGo + RT ln(P(I2))

Here

ΔGo represent the free energy change under standard conditions

ΔG represents the free energy change under actual conditions.

Now

For solid iodine placed in the open air, P(I2) is closely small (close to 0), and ln(P(I2)) refers to a large negative value,

Therefore ΔG = ΔGo + RT ln(P(I2)) is also a large negative value.

Since ΔG < 0, the sublimation reaction should be thermodynamically favorable and spontaneous.

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