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Henry has a fair number pyramid with four faces and a spinner with three equal sized colored sections. what is the probability that the number pyramid will land on three and the spinner will stop on blue?

Respuesta :

texaschic101
P(pyramid landing on 3) = 1/4
P(spinner stopping on blue) = 1/3

P(both) = 1/4 * 1/3 = 1/12 <===
JeanaShupp

Answer: [tex]\dfrac{1}{12}[/tex]

Step-by-step explanation:

Given : The number of faces in a fair number pyramid (1,2,3,4) =4

Let A be the event that number pyramid will land on three.

Then, [tex]P(A)=\dfrac{1}{4}[/tex]

The number of equal sized colored sections in spinners= 3

Let B be the event that  the spinner will stop on blue.

Then, [tex]P(B)=\dfrac{1}{3}[/tex]

Since, both the events A and B are independent.

Thus, the probability that the number pyramid will land on three and the spinner will stop on blue is given by :-

[tex]P(A\cap B)=P(A)\times P(B)\\\\=\dfrac{1}{4}\times\dfrac{1}{3}=\dfrac{1}{12}[/tex]

Hence, the probability that the number pyramid will land on three and the spinner will stop on blue =[tex]\dfrac{1}{12}[/tex]

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