Respuesta :
f(c) = (2 * c) + 1
when c = 1
f(1) = (2 * 1) + 1
f(1) = 3 <== range
when c = 2
f(2) = (2 * 2) + 1
f(2) = 5 <== range
when c = 3
f(3) = (2 * 3) + 1
f(3) = 7 <== range
range (all the f(c)'s) = {3,5,7}
when c = 1
f(1) = (2 * 1) + 1
f(1) = 3 <== range
when c = 2
f(2) = (2 * 2) + 1
f(2) = 5 <== range
when c = 3
f(3) = (2 * 3) + 1
f(3) = 7 <== range
range (all the f(c)'s) = {3,5,7}
Answer:
Range of function is {3,5,7}
Step-by-step explanation:
We have been given an expression:
f(c)=(2 x c)+1
We will substitute given values of c in f(c) to find f(c)
when c=1
f(c)=(2 x 1)+1=3
when c=2
f(c)=(2 x 2)+1=5
when c=3
f(c)=(2 x 3)+1=7
Hence, Range is the values f(c) will take
So, the values of f(c) are 3,5,7
Hence, range of function is {3,5,7}