Answer: (A) - [tex]\frac{19\sqrt{3}}{6}[/tex]
Proof: [tex]\sqrt{\frac{75}{4}} = \frac{5\sqrt{3}}{2}[/tex]
[tex]\sqrt{\frac{12}{9}} = \frac{2\sqrt{3}}{3}[/tex]
Hence, [tex]\sqrt{\frac{75}{4}} + \sqrt{\frac{12}{9}}[/tex]
[tex]= \frac{5\sqrt{3}}{2} + \frac{2\sqrt{3}}{3}[/tex]
[tex]= \frac{15\sqrt{3} + 4\sqrt{3}}{6}[/tex]
[tex]= \frac{19\sqrt{3}}{6}[/tex] (ie A)
