Respuesta :

DeanWinchester16
You'd use the temperature change equation. The specific heat of water is always 4.18J/(g °C).
Equation to use: q=mCΔT

21.8=(2.0)(4.18)(Tf-5)
21.8=(8.36)(Tf-5)
21.8/8.36=Tf-5
2.61=Tf-5
2.61+5=Tf
Tf=7.61 °C

Since you want to know how many °C it raises, you wouldn't pay attention to the last 2 steps, however if you need to know the final temp, you want to go to the last step.
okpalawalter8

A 2.0g sample of water at 5.0celcius absorbs 21.8 Joules of energy, the temperature of the sample will be raised by dT=7.61 °C

What will the temperature of the sample be raised by?

Question Parameter(s):

if a 2.0g sample of water

at 5.0celcius absorbs 21.8Joules of energy,

Generally, the equation for the Heat  is mathematically given as

q=mCΔT

Therefore

21.8=(2.0)(4.18)(dT-5)

2.61=dT-5

dT=7.61 °C

In conclusion, the temperature is

dT=7.61 °C

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