Respuesta :
.5A = A(1 - 0.1)^t
.5 = (0.9)^t
log_(0.9)(0.5) = t
t = ln(.5)/ln (.9)
The car is approximately 7 years old
.5 = (0.9)^t
log_(0.9)(0.5) = t
t = ln(.5)/ln (.9)
The car is approximately 7 years old
Answer:
[tex]t=6.578813479\approx 7\hspace{3}years[/tex]
Step-by-step explanation:
Basically we need to find the value of t, according to the data suply by the problem. The problem gives this equation:
[tex]y=A(1-r)^t[/tex]
In this case, the problem tell us:
[tex]y=\frac{A}{2} \\r=10\%=0.1[/tex]
Replacing the data in the equation:
[tex]\frac{A}{2} =A(1-0.1)^t[/tex]
Divide both sides by A:
[tex]\frac{A}{2A}=\frac{A}{A}(1-0.1)^t\\\frac{1}{2} =(0.9)^t[/tex]
Now, simply take the logarithm base 0.9 of both sides:
[tex]log_0_._9(\frac{1}{2})=log_0_._9(0.9)^t\\ \\6.578813479=t[/tex]
Therefore:
[tex]t=6.578813479\approx 7\hspace{3}years[/tex]
The car is approximately 7 years old