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Mr. Hernandez's backyard is shaped like a trapezoid with a height of 10 m, a top base of 15 m, and a bottom base of 19 m. The area of the backyard without the garden is 141.74 squared meters.
How to find the area of a trapezoid?
The area of a trapezoid is half of the product of sum of its parallel sides to the height of that trapezoid (the distance between those parallel sides).
Thus, if we have:
Length of its parallel sides = 'a' and 'b' units respectively
Perpendicular distance between its parallel sides = 'h' units,
Then, we get:
[tex]A = \dfrac{1}{2}\times(a+b) \times h \: \rm unit^2[/tex]
Mr. Hernandez's backyard is shaped like a trapezoid.
The height of the backyard = 10 m.
The top base of the backyard = 15 m.
The bottom base of the backyard = 15 m.
Thus the area of the trapezoid backyard is,
[tex]A = \dfrac{15+ 19}{2} \times 10\\\\A = 17 \times 10\\\\A = 170[/tex]
Thus the area of the 3 m radius garden is,
[tex]A = 3.14 \times 9\\\\A = 28.26[/tex]
The area of the backyard without the garden is the area of the total background subtracted from the area of the circular garden.
Thus,
A = 170 - 28.26
A = 141.74
Thus the area of the backyard without the garden is 141.74 squared meters.
Learn more about the area of the trapezoid here;
brainly.com/question/397536
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